Integrand size = 24, antiderivative size = 139 \[ \int \frac {x^2 \arctan (a x)^2}{\left (c+a^2 c x^2\right )^{5/2}} \, dx=-\frac {2 x^3}{27 c \left (c+a^2 c x^2\right )^{3/2}}-\frac {4 x}{9 a^2 c^2 \sqrt {c+a^2 c x^2}}+\frac {2 x^2 \arctan (a x)}{9 a c \left (c+a^2 c x^2\right )^{3/2}}+\frac {4 \arctan (a x)}{9 a^3 c^2 \sqrt {c+a^2 c x^2}}+\frac {x^3 \arctan (a x)^2}{3 c \left (c+a^2 c x^2\right )^{3/2}} \]
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Time = 0.19 (sec) , antiderivative size = 139, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {5064, 5058, 5050, 197} \[ \int \frac {x^2 \arctan (a x)^2}{\left (c+a^2 c x^2\right )^{5/2}} \, dx=\frac {2 x^2 \arctan (a x)}{9 a c \left (a^2 c x^2+c\right )^{3/2}}+\frac {x^3 \arctan (a x)^2}{3 c \left (a^2 c x^2+c\right )^{3/2}}-\frac {4 x}{9 a^2 c^2 \sqrt {a^2 c x^2+c}}-\frac {2 x^3}{27 c \left (a^2 c x^2+c\right )^{3/2}}+\frac {4 \arctan (a x)}{9 a^3 c^2 \sqrt {a^2 c x^2+c}} \]
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Rule 197
Rule 5050
Rule 5058
Rule 5064
Rubi steps \begin{align*} \text {integral}& = \frac {x^3 \arctan (a x)^2}{3 c \left (c+a^2 c x^2\right )^{3/2}}-\frac {1}{3} (2 a) \int \frac {x^3 \arctan (a x)}{\left (c+a^2 c x^2\right )^{5/2}} \, dx \\ & = -\frac {2 x^3}{27 c \left (c+a^2 c x^2\right )^{3/2}}+\frac {2 x^2 \arctan (a x)}{9 a c \left (c+a^2 c x^2\right )^{3/2}}+\frac {x^3 \arctan (a x)^2}{3 c \left (c+a^2 c x^2\right )^{3/2}}-\frac {4 \int \frac {x \arctan (a x)}{\left (c+a^2 c x^2\right )^{3/2}} \, dx}{9 a c} \\ & = -\frac {2 x^3}{27 c \left (c+a^2 c x^2\right )^{3/2}}+\frac {2 x^2 \arctan (a x)}{9 a c \left (c+a^2 c x^2\right )^{3/2}}+\frac {4 \arctan (a x)}{9 a^3 c^2 \sqrt {c+a^2 c x^2}}+\frac {x^3 \arctan (a x)^2}{3 c \left (c+a^2 c x^2\right )^{3/2}}-\frac {4 \int \frac {1}{\left (c+a^2 c x^2\right )^{3/2}} \, dx}{9 a^2 c} \\ & = -\frac {2 x^3}{27 c \left (c+a^2 c x^2\right )^{3/2}}-\frac {4 x}{9 a^2 c^2 \sqrt {c+a^2 c x^2}}+\frac {2 x^2 \arctan (a x)}{9 a c \left (c+a^2 c x^2\right )^{3/2}}+\frac {4 \arctan (a x)}{9 a^3 c^2 \sqrt {c+a^2 c x^2}}+\frac {x^3 \arctan (a x)^2}{3 c \left (c+a^2 c x^2\right )^{3/2}} \\ \end{align*}
Time = 0.11 (sec) , antiderivative size = 80, normalized size of antiderivative = 0.58 \[ \int \frac {x^2 \arctan (a x)^2}{\left (c+a^2 c x^2\right )^{5/2}} \, dx=\frac {\sqrt {c+a^2 c x^2} \left (-2 a x \left (6+7 a^2 x^2\right )+6 \left (2+3 a^2 x^2\right ) \arctan (a x)+9 a^3 x^3 \arctan (a x)^2\right )}{27 a^3 c^3 \left (1+a^2 x^2\right )^2} \]
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Result contains complex when optimal does not.
Time = 1.61 (sec) , antiderivative size = 272, normalized size of antiderivative = 1.96
method | result | size |
default | \(\frac {\left (6 i \arctan \left (a x \right )+9 \arctan \left (a x \right )^{2}-2\right ) \left (a^{3} x^{3}-3 i a^{2} x^{2}-3 a x +i\right ) \sqrt {c \left (a x -i\right ) \left (a x +i\right )}}{216 \left (a^{2} x^{2}+1\right )^{2} a^{3} c^{3}}+\frac {\left (\arctan \left (a x \right )^{2}-2+2 i \arctan \left (a x \right )\right ) \left (a x -i\right ) \sqrt {c \left (a x -i\right ) \left (a x +i\right )}}{8 c^{3} a^{3} \left (a^{2} x^{2}+1\right )}+\frac {\sqrt {c \left (a x -i\right ) \left (a x +i\right )}\, \left (a x +i\right ) \left (\arctan \left (a x \right )^{2}-2-2 i \arctan \left (a x \right )\right )}{8 c^{3} a^{3} \left (a^{2} x^{2}+1\right )}+\frac {\left (-6 i \arctan \left (a x \right )+9 \arctan \left (a x \right )^{2}-2\right ) \sqrt {c \left (a x -i\right ) \left (a x +i\right )}\, \left (a^{3} x^{3}+3 i a^{2} x^{2}-3 a x -i\right )}{216 \left (a^{4} x^{4}+2 a^{2} x^{2}+1\right ) a^{3} c^{3}}\) | \(272\) |
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Time = 0.25 (sec) , antiderivative size = 88, normalized size of antiderivative = 0.63 \[ \int \frac {x^2 \arctan (a x)^2}{\left (c+a^2 c x^2\right )^{5/2}} \, dx=\frac {{\left (9 \, a^{3} x^{3} \arctan \left (a x\right )^{2} - 14 \, a^{3} x^{3} - 12 \, a x + 6 \, {\left (3 \, a^{2} x^{2} + 2\right )} \arctan \left (a x\right )\right )} \sqrt {a^{2} c x^{2} + c}}{27 \, {\left (a^{7} c^{3} x^{4} + 2 \, a^{5} c^{3} x^{2} + a^{3} c^{3}\right )}} \]
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\[ \int \frac {x^2 \arctan (a x)^2}{\left (c+a^2 c x^2\right )^{5/2}} \, dx=\int \frac {x^{2} \operatorname {atan}^{2}{\left (a x \right )}}{\left (c \left (a^{2} x^{2} + 1\right )\right )^{\frac {5}{2}}}\, dx \]
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none
Time = 0.27 (sec) , antiderivative size = 117, normalized size of antiderivative = 0.84 \[ \int \frac {x^2 \arctan (a x)^2}{\left (c+a^2 c x^2\right )^{5/2}} \, dx=\frac {1}{3} \, {\left (\frac {x}{\sqrt {a^{2} c x^{2} + c} a^{2} c^{2}} - \frac {x}{{\left (a^{2} c x^{2} + c\right )}^{\frac {3}{2}} a^{2} c}\right )} \arctan \left (a x\right )^{2} - \frac {2 \, {\left (7 \, a^{3} x^{3} + 6 \, a x - 3 \, {\left (3 \, a^{2} x^{2} + 2\right )} \arctan \left (a x\right )\right )} a}{27 \, {\left (a^{6} c^{2} x^{2} + a^{4} c^{2}\right )} \sqrt {a^{2} x^{2} + 1} \sqrt {c}} \]
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\[ \int \frac {x^2 \arctan (a x)^2}{\left (c+a^2 c x^2\right )^{5/2}} \, dx=\int { \frac {x^{2} \arctan \left (a x\right )^{2}}{{\left (a^{2} c x^{2} + c\right )}^{\frac {5}{2}}} \,d x } \]
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Timed out. \[ \int \frac {x^2 \arctan (a x)^2}{\left (c+a^2 c x^2\right )^{5/2}} \, dx=\int \frac {x^2\,{\mathrm {atan}\left (a\,x\right )}^2}{{\left (c\,a^2\,x^2+c\right )}^{5/2}} \,d x \]
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